A number is three times the sum of its digit. What is the number?

 A number is three times the sum of its digit. What is the number?👇🏾👇 🏾



👇🏾👇 🏾




Let the number be denoted as

𝑎𝑏ab

, where

𝑎 and 𝑏 are the digits. Since 𝑎𝑏ab

represents a two-digit number, it can be expressed mathematically as:

10𝑎+𝑏𝑎+𝑏10𝑎+𝑏=3(𝑎+𝑏)10𝑎+𝑏=3𝑎+3𝑏3𝑎+3𝑏 from both sides:10𝑎+𝑏3𝑎3𝑏=07𝑎2𝑏=0𝑏:7𝑎=2𝑏    𝑏=7𝑎227a

According to the problem, the number is three times the sum of its digits. The sum of its digits is:

Thus, we have the equation:

Expanding and simplifying this equation:

Subtract

This simplifies to:

Solving for

Since

𝑎 and 𝑏 are digits, 𝑎 must be chosen such that 𝑏 is an integer between 0 and 9. Therefore, 7𝑎 must be divisible by 2, meaning 𝑎 must be even.𝑎:𝑎=2𝑏=7×22=7    Number is 2727×2

We test even values of

  1. :

    𝑎=4𝑏=7×42=14    Invalid since 𝑏 is not a digit27×4

  2. :

    𝑎 since they would yield 𝑏 greater than 9.27=3×(2+7)=3×9=2727Thus, the number that satisfies the given condition is: 27 [ans 27]

No need to test higher even values of

So, we verify the candidate number 27:


Post a Comment

Previous Post Next Post